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90.0 g of Ca(NO3)2 was used to create a 2.6 M solution. What is the volume of the solution? (Ca(NO3)2 = 164.0878 g/mol)
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90.0 g of Ca(NO3)2 was used to create a 2.6 M solution. What is the volume of the solution? (Ca(NO3)2 = 164.0878 g/mol)

User TonnyL
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1 Answer

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The concentration of a solution is:
concentration = moles / volume (dm³)

The moles of calcium nitrate:
moles = mass / Mr
moles = 90 / 164.0878
moles = 0.55

2.6 = 0.55 / volume
Volume = 0.211 dm³
Volume = 211 cm³

User Fdrv
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