Question

A drag-racing car goes fro 0 to 300mph in 5 seconds. What is its average acceleration in g's?

Answer 1

The drag-racing car's average acceleration from 0 to 300mph in 5 seconds is approximately 2.73 g's, after converting the speed to meters per second and using the formula for average acceleration.

Step-by-step explanation:

To calculate the average acceleration in g's for a drag-racing car that goes from 0 to 300mph in 5 seconds, we need to first convert the speed from miles per hour (mph) to meters per second (m/s). Since 1 mph is approximately 0.44704 m/s, 300 mph equals roughly 134.112 m/s. The formula for average acceleration (a) is given by the change in velocity (Δv) divided by the time (t) it takes for the change to occur, a = Δv / t.

Using the conversion for 300 mph, we have an initial velocity (u) of 0 m/s and a final velocity (v) of 134.112 m/s over a time (t) of 5 seconds. Therefore, the average acceleration is:

a = (134.112 m/s - 0 m/s) / 5 s = 26.8224 m/s²

Earth's gravitational acceleration (g) is 9.81 m/s², so to express the car's acceleration in g's, we divide the car's acceleration by Earth's gravitational acceleration:

a in g's = 26.8224 m/s² / 9.81 m/s² ≈ 2.73 g's

Thus, the drag-racing car's average acceleration is approximately 2.73 g's.

Answer 2

I think that the short answer to this question is to convert 300mph into metres per second, and then divide by 5 to get the average acceleration. Since 1g is, I think, 9.81 m/s^2 (nearly 10), dividing by 9.81 should give the number of gs in the acceleration.1 mile is 1760 yards which is 1760x3 feet which is 1760x3x12 inches.300 miles would be 300x1760x3x12 inches.1 inch is 2.54 cm.300 miles would be 2.54x300x1760x3x12 cm.300 miles would be 2.54x300x1760x3x12/100 m.Then do the number of seconds in an hour.I hope this helps ...