Question

How many sides does a polygon have if the sum of its interior angle measures is 7380?

Answer 1

`\bf \textit{sum of interior angles}=180(n-2)\qquad n=\textit{number of sides} \\\\ \textit{now, we know the sum of its interior angles is 7,380}\qquad thus \\\\ 7,380=180(n-2)`

solve for "n"