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How many sides does a polygon have if the sum of its interior angle measures is 7380?
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How many sides does a polygon have if the sum of its interior angle measures is 7380?

User Shendy
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\bf \textit{sum of interior angles}=180(n-2)\qquad n=\textit{number of sides} \\\\ \textit{now, we know the sum of its interior angles is 7,380}\qquad thus \\\\ 7,380=180(n-2)

solve for "n"
User James Michael Hare
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