Question

The midpoint of AB is M(4,1). If the coordinates of A are (2,8), what are thecoordinates of B?

Answer 1

`\begin{gathered} \text{mid point = (}(x_1+x_2)/(2),(y_1+y_2)/(2)\text{)} \\ (4,1)\text{ = (}(2+x_2)/(2),(8+y_2)/(2)\text{)} \\ (2+x_2)/(2)=4 \\ 2+x_2=8 \\ x_2=8-2 \\ x_2=6 \\ \\ (8+y_2)/(2)=1 \\ 8+y_2=2 \\ y_2=2-8 \\ y_2=-6 \\ B=(6,-6) \end{gathered}`