Question

Find the coordinates of the center, vertices, covertices, foci, length of transverse and conjugate axis and the equation of the asymptotes. Then graph the hyperbola.

Answer 1

The given equation is,

`(x^2)/(36)-(y^2)/(16)=1\text{ ---(1)}`

It can be rewritten as,

`(x^2)/(6^2)-(y^2)/(4^2)=1\text{ ---(2)}`

The above equation is similar to the standard equation of left-right facing a hyperbola given by,