180k views
1 vote
How many moles of sodium chloride (NaCl) solute are in 315 grams of a 91.0 percent by mass solution?

3.46 mol NaCl
4.90 mol NaCl
5.37 mol NaCl
5.92 mol NaCl

User Exceen
by
5.7k points

2 Answers

3 votes

Final answer:

To find the moles of NaCl solute in the solution, multiply the mass of the solution by the mass percent, convert the mass of NaCl to moles using the molar mass, and divide by the mass of the solution. In this case, there are approximately 4.91 moles of NaCl in 315 grams of the solution.

Step-by-step explanation:

To calculate the moles of sodium chloride (NaCl) solute in the solution, we need to know the mass of solute and the mass percent of the solution. In this case, we are given that the solution is 91.0 percent by mass and has a mass of 315 grams.

First, we calculate the mass of NaCl in the solution: 315 grams x 0.910 = 286.65 grams NaCl.

Next, we convert the mass of NaCl to moles using the molar mass of NaCl (58.44 g/mol): 286.65 grams / 58.44 g/mol = 4.91 moles NaCl.

Therefore, there are approximately 4.91 moles of NaCl solute in 315 grams of the 91.0 percent by mass solution.

User Chauncy Zhou
by
6.3k points
5 votes
Hope this helps you.
How many moles of sodium chloride (NaCl) solute are in 315 grams of a 91.0 percent-example-1
How many moles of sodium chloride (NaCl) solute are in 315 grams of a 91.0 percent-example-2
User Gaurav Fotedar
by
6.1k points