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14 votes
14 votes
Michael wants to save $55,000.00 for a down payment on a home. How much will he need to invest in anaccount with 8.5% APR, compounding daily, in order to reach his goal in 3 years?

User Re
by
2.6k points

1 Answer

19 votes
19 votes

Step 1. The information that we have is:

The final amount that Michael wants to save is:


A=55,000

We will call that amount A.

The annual percentage rate of the investment, which we will label as r, is:


r=8.5

We will need this annual percentage rate represented as a decimal number, therefore, we divide it by 100:


\begin{gathered} r=8.5/100 \\ r=0.085 \end{gathered}

The time of the investment, t, is 3 years:


t=3

And it is compounded daily, let n be the number of times of compounding in a year:


n=365

Step 2. We need to find the initial amount of the investment, which will be called P or principal.

The formula we will use to find it is:


A=P(1+(r)/(n))^(nt)

Step 3. Substituting the known values:


55,000=P(1+(0.085)/(365))^((365)(3))

From this equation, we need to solve the operations and solve for P, the principal amount of the investment.

Step 4. Simplifying the equation:


55,000=P(1+0.0002328767)^(1095)

Continue simplifying:


\begin{gathered} 55,000=P(1.0002328767)^(1,095) \\ 55,000=P(1.2904233) \end{gathered}

Then, we solve for P:


\begin{gathered} (55,000)/(1.2904233)=P \\ 42,621.6726=P \end{gathered}

Rounding to the nearest cent (2 decimal places) The amount that he needs to invest is $42,621.67

Answer: $42,621.67

User Carlyn
by
2.9k points
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