Question

According to the punnett square: b represents the dominant gene for blue feathers and b represents the recessive gene for red feathers. two heterozygous birds have one offspring. what percent chance does it have for red feathers?

a. 0%
b. 25%
c. 75%
d. 100%

Answer 1

B. 25% because Bb x Bb= Bb, Bb, Bb, and bb. The only one that will actually show the red feathers is the completely receive one: bb. This is only 1/4 which equals 25%

Answer 2

Answer;

B. 25 %

Explanation;

• B-represents the dominant gene for blue feathers therefore, a homozygous dominant would be BB, which would be blue feathers,
• b- represents a recessive gene for red feathers, thus dominant recessive would be bb, which will be red feathers. Therefore, a heteroztygous will be Bb, and the phenotype will be blue feathers.
• When heterozygous dominant are closed; that is, Bb x Bb, the offsprings will either be Bb, Bb, Bb, or bb. The only one that will actually show the red feathers is the recessive one: bb, which is only 1/4 which equals 25%.