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Find the dimensions of a rectangle whose width is 7 miles less than its length and whose areas is 78 square miles.
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Find the dimensions of a rectangle whose width is 7 miles less than its length and whose areas is 78 square miles.
asked
Dec 7, 2018
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Find the dimensions of a rectangle whose width is 7 miles less than its length and whose areas is 78 square miles.
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W = L - 7
WL = 78
(L-7)L = 78
L^2 - 7L - 78 = 0
Factorize: (L-13)(L+6) = 0
L = 13 or -6
A length cannot be negative, so the
length must be 13 miles
.
The width is 13-7 = 6 miles.
TheNeil
answered
Dec 14, 2018
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TheNeil
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