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25 votes
25 votes
A ball bounces to a height of 6.1 feet on the first bounce. Each subsequent bounce reaches a height that is 82% of the previous bounce. What is the height, in feet, of the fifth bounce? Round your answer to the thousandths place.

User Ganga
by
2.4k points

1 Answer

16 votes
16 votes

In the first bounce, the height is


6.1*(0.82)^0=6.1

In the second bounce, the height is


6.1*(0.82)^2=5.002

Then, we can note that the pattern is


6.1*(0.82)^(n-1)

where n represents the number of bounces of the ball. Then, for n=5 (fifth bounce), we get


\begin{gathered} 6.1*(0.82)^(5-1) \\ 6.1*(0.82)^4 \end{gathered}

which gives


6.1*(0.82)^4=2.7579

Therefore, by rounding to the nearest thousandths, the answer is 2.758 feet

User Benez
by
2.5k points
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