Question

7. 4×= 3yy=-4x + 39. y+2=0x+ 2 = 011.x-5y=45x + y = 4Determine if the graphs will show parallel or perpendicular lines, or neither.

Answer 1

Given:

`\begin{gathered} 4x=3y \\ y=-4x+3 \end{gathered}`

Sol:.

If the both line are perpendicular then multipilcation of slope is -1 then:

`\begin{gathered} y=mx+c \\ m=\text{slope} \\ \end{gathered}`
`\begin{gathered} 3y=4x \\ y=(4)/(3)x \\ m_1=(4)/(3) \end{gathered}`
`\begin{gathered} y=-4x+3 \\ m_2=-4 \end{gathered}`
`\begin{gathered} =m_1m_2 \\ =(4)/(3)*-4 \\ m_1m_2\\e-1 \\ \text{That mean its not perpendicular } \end{gathered}`

For parallel line slope are same then its not a parallel line

So line neither perpendicular or parallel.