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A flask contains 0.340 mol of liquid bromine, br2. determine the number of bromine molecules present in the flask.

User Shaun Han
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2 Answers

1 vote

Answer:
2.05* 10^(23) molecules

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number
6.023* 10^(23) of particles.

1 mole of
Br_2 contains =
6.023* 10^(23) molecules of bromine

0.340 mole of
Br_2 contains =
(6.023* 10^(23))/(1)* 0.340=2.05* 10^(23) molecules of bromine

Thus there are
2.05* 10^(23) molecules of bromine present in the flask.

User Rizzer
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7.8k points
2 votes
Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. We calculate as follows:

0.340 mol Br2 ( 6.022 x 10^23 molecules / mol ) = 2.05 x 10^23 molecules
User Jonathon Fry
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8.3k points