Question

Please help me noone will help i just need two questions answered someone for the love of god please hELp

me

Answer 1

5 - Solving:
Answer: Formula P.G
`\boxed{A(n) = a*r^(n-1)}`

6- Solving
Collecting the data of this P.G., comes:

The 1st term
`a_(1) = 9`
The 2nd term
`a_(2) = 12`
The 3rd term
`a_(3) = 16`
The 4th term
`a_(4) = 21(1)/(3) = (64)/(3)`

It is a geometric progression (P.G), since the ratio of
`( a_(2) )/( a_(1) ) = ( a_(4) )/( a_(3))`
The ratio
`r = \frac {a2}{a1}`
The ratio
`r = \frac {a4}{a3}`

The value of ratio, we have:

`r = \frac {a2}{a1}`

`r = \frac {12}{9}`
simplify by 3

`r = \frac {12}{9}(/3)/(/3) \to\: \boxed{\boxed{r = (4)/(3)}}\end{array}}\qquad\quad\checkmark`
The value of ratio, we have:


`r = \frac {a4}{a3}`

`r = ( (64)/(3) )/(16)`

`r = (64)/(3) * (1)/(16) = (64)/(48)`
Simplify by 16

`r = (64)/(48) (/16)/(/16) \to\:\boxed{\boxed{r = (4)/(3) }}\end{array}}\qquad\quad\checkmark`



Answer:

`\underline{Geometric\:with\:a\:common\:ratio\:of}`
`\boxed{\boxed{r = (4)/(3)}}`