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I need to know how to solve for the value of x
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Sep 1, 2018
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I need to know how to solve for the value of x
Mathematics
high-school
Sourav Kannantha B
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Sourav Kannantha B
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Hey Katie
4^2x+3 = 1
We need to solve for x
log(4^2x+3) = log (1)
Now take log of
(2x +3) * log (4) = log (1)
2x + 3 = log(1)/log(4)
2x + 3 = 0
2x = 0 - 3
2x = -3
x = -3/2
I hope that's help !
Gwaredd
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Sep 5, 2018
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Gwaredd
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