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2. Solve the following system of equations using substitution.

2x+2y=38
Y=x+3

A.(8,11)
B.(4,7)
C.(35/4, 47/4)
D.(-4,-7)

1 Answer

2 votes
First, make sure you convert both equations into standard form. Your two equations would be 2x+2y=38 and -x+y=3. Then multiply the bottom by 2. So your new equations would be 2x+2y=38 and -2x+2y=6. The x would cancel out and you would continue solving for y. y would equal 11 and then you would plug it back into an original equation. When you plug and solve for x, you would get x=8. So your answer would be (8,11)
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