Question

Solve the following literal equation for b. 3ab - z = y(4ab + 2z)

Answer 1

b= z(1+2y)/a(3-4y)        I hoped this helped you answer the question!

Answer 2

`b=(z(2y+1))/(a(3-4y))` for
`a(3-4y)\\eq 0`.

Explanation:

The given equation is

`3ab-z=y(4ab+2z)`

We need to solve the above equation for b.

Using distributive property we get

`3ab-z=y(4ab)+y(2z)`

`3ab-z=4aby+2yz`

Subtract 4aby from both sides.

`3ab-z-4aby=2yz`

Add z on both sides.

`3ab-4aby=2yz+z`

Taking out the common factor.

`ab(3-4y)=z(2y+1)`

Divide both sides by a(3-4y).

`b=(z(2y+1))/(a(3-4y))`

Therefore the value of b is
`b=(z(2y+1))/(a(3-4y))` for
`a(3-4y)\\eq 0`.