Question

Find the solutions to the following quadratic equation negative 3X squared plus 4X plus one equals zero (-3x^2 + 4x + 1 = 0)

Answer 1

Step-by-step explanation:

Given:

`-3x^2+4x+1=0`

To find:

the value of x using the quadratic formula

The quadratic formula is given as:

`$$x\text{ = }\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$$`

where a = -3, b = 4, c = 1

`\begin{gathered} x\text{ = }(-4\pm√((4)^2-4(-3)(1)))/(2(-3)) \\ \\ x\text{ = }(-4\pm√(16+12))/(-6) \\ \\ x\text{ = }(-4\pm√(28))/(-6) \end{gathered}`