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Arc length of y= -0.1480x^3+1.353x^2-4.068x+5.651 from x=0.2 to x=5.25

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y=-0.1480x^3+1.353x^2-4.068x+5.651

\implies y'=-0.444x^2+2.706x-4.068

The arc length is given by the integral


\displaystyle\int_(0.2)^(5.25)√(1+(y')^2)\,\mathrm dx

which has a value of about
7.6683.
User Truong Ha
by
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