45,848 views
39 votes
39 votes
A baseball of mass 1.23 kg is thrown at a speed of 65.8 mi/h. What is its kinetic energy?

User Davidwessman
by
2.8k points

1 Answer

9 votes
9 votes

Given:

The mass of the ball is


m=1.23\text{ kg}

The speed of the ball is


\begin{gathered} v=65.8\text{ mi/h} \\ \end{gathered}

Required: calculate the kinetic energy of the baseball

Step-by-step explanation: to calculate the kinetic energy of a body we will use the formula as


K.E=(1)/(2)mv^2

first, we convert velocity from mi/h into m/s.

we know that


1\text{ mi=1609.34 m}

and


1\text{ h=3600 sec}

then the velocity is


\begin{gathered} v=\frac{65.8*1602.34\text{ m}}{3600\text{ s}} \\ v=29.29\text{ m/s} \end{gathered}

now plugging all the values in the above formula, we get


\begin{gathered} K.E=(1)/(2)mv^2 \\ K.E=(1)/(2)*1.23\text{ kg}*(29.29\text{ m/s})^2 \\ K.E=527.61\text{ J} \end{gathered}

Thus, the kinetic energy of the baseball is


527.61\text{ J}

User Tirza
by
2.4k points