Question

How to solve 4(a+1)=12how to solve 13+2k=5+4khow to solve -4e+28=10ehow to solve -6(4+c)=-66

Answer 1

In this problem, we must solve some linear equations.

1)

`\begin{gathered} 4\cdot(a+1)=12, \\ a+1=(12)/(4), \\ a+1=3, \\ a=3-1, \\ a=2. \end{gathered}`

2)

`\begin{gathered} 13+2k=5+4k, \\ 13-5+2k=4k, \\ 8+2k=4k, \\ 4k-2k=8 \\ 2k=8, \\ k=(8)/(2), \\ k=4. \end{gathered}`

3)

`\begin{gathered} -4e+28=10e, \\ 28=10e+4e, \\ 28=14e, \\ e=(28)/(14), \\ e=2. \end{gathered}`

4)

`\begin{gathered} -6(4+c)=-66, \\ 4+c=(-66)/(-6), \\ 4+c=11, \\ c=11-4, \\ c=7. \end{gathered}`

Answers

• a = 2

,

• k = 4

,

• e = 2

,

• c = 7