Question

What mass of NH3 can be made from 35.0g of N2?

Answer 1

formation of ammonia by nitrogen and hydrogen is habers process wher 28g N2 results in formation of 34g NH3
so 35g N2 will form 34*35/28=42.5g NH3 where it given that reaction takes place in excess of H2
N2+3H2 gives 2NH3

Answer 2

`Mass_(NH_3)= 42.5775\ g`

Step-by-step explanation:

Moles of
`N_2`:-

Mass = 35.00 g

Molar mass of
`N_2` = 28.014 g/mol

The formula for the calculation of moles is shown below:

`moles = (Mass\ taken)/(Molar\ mass)`

Thus,

`Moles= (35.00\ g)/(28.014\ g/mol)`

`Moles_(N_2)= 1.25\ mol`

According to the reaction:-

`N_2_((g)) + 3H_2_((g))\rightarrow 2NH_3_((g))`

1 mole of
`N_2` on reaction forms 2 moles of
`NH_3`

1.25 mole of
`N_2` on reaction forms 2*1.25 moles of
`NH_3`

Moles of
`NH_3` = 2.5 moles

Molar mass of
`NH_3` = 17.031 g/mol

The formula for the calculation of moles is shown below:

`moles = (Mass\ taken)/(Molar\ mass)`

Thus,

`2.5\ mol= (Mass)/(17.031\ g/mol)`

`Mass_(NH_3)= 42.5775\ g`