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If Isaac has 21 green marbles and 7 blue marbles and wants to make equal groups with none left over, what is the greatest number of groups he can make?
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If Isaac has 21 green marbles and 7 blue marbles and wants to make equal groups with none left over, what is the greatest number of groups he can make?

User Highstead
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1 Answer

1 vote
The greatest number of groups would probably be 7 because:
21+7 = 28
28: 1, 2, 4, 7, 14
28/2 = 14
Half of 28 is 14 which means that each group will have 2 marbles. I am not sure if I'm correct, but I hope this helps! :)

User Shafiqul Islam
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