Question

The density of lead is 11.3

g/mL
. The water level in a graduated cylinder initially at 206
mL
rises to 287
mL
after a piece of lead is submerged. What is the mass in grams of the lead?

Answer 1

Volume = 287 - 206
v= 81 mL

Mass= density x volume
m = 11.3 x 81
m = 915.3 g

Answer 2

915 g

Step-by-step explanation:

The volume of lead (V) is equal to the difference between the final level of water and the initial level of water.

V = 287 mL - 206 mL = 81.0 mL

The density of lead (ρ) is 11.3 g/mL. We can find the mass of lead (m), in grams, using the following expression.

ρ = m/V

m = ρ × V

m = 11.3 g/mL × 81.0 mL

m = 915 g