87.6k views
0 votes
The vertex of this parabola is at (4, -3). when the x-value is 5, the y-value is -6. what is the coefficient of the squared expression in the parabola's equation?

*sorry edited now 

User Asgu
by
8.5k points

1 Answer

4 votes

\bf y=a(x-\boxed{h})^2+\boxed{k}\qquad vertex\ (h,k) \\ \quad \\ \textit{we know the vertex is at 4,-3}\implies \begin{array}{lrlll} 4&-3\\ h&k \end{array} \\ \quad \\ y=a(x-h)^2+k\\\\ y=a(x-(4))^2+(-3)\implies y=a(x-4)^2-3 \\ \quad \\ \textit{we also know that} \begin{cases} x=5\\ y=-6 \end{cases}\textit{ so, what is the coefficient
User YelizavetaYR
by
7.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories