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if the velocity of a car is halved the fc required to keeo it in a path of constant radius is multiplied/divided by?
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if the velocity of a car is halved the fc required to keeo it in a path of constant radius is multiplied/divided by?

User Samuraisam
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1 vote
it should be the 4... so the answer is 4...
User John Szakmeister
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4 votes
I believe this is it
The centripetal force is given by
F = mv^2 / r
When v' = v/2,
F' = mv'^2/r = m(v/2)^2/r = mv^2/4r = F/4.
So the centripetal force is divided by 4.
User Omar Bahareth
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