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Solve this problem in your notebook using all four steps. Harvey is 3 times as old as Jane. The sum of their ages is 48 years. Find the age of each. Jane is a0 years old. Harvey is a1 years old.

1 Answer

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Harvey is 3 times as old as Jane."
h = 3j

"The sum of their ages is 48 years."
h + j = 48

substitution
(3j) + j = 48
4j = 48
j = 12
h = 3j = 36
User Daniel Passos
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