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A 1451 kg car is traveling at 48.0 km/h. How much kinetic energy does it possess? K.E. = 1.67 x 105 J 9.65 x 105 J 1.28 x 105 J 3.48 x 105 J
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A 1451 kg car is traveling at 48.0 km/h.

How much kinetic energy does it possess? K.E. =

1.67 x 105 J

9.65 x 105 J

1.28 x 105 J

3.48 x 105 J

User Atrotygma
by
6.3k points

2 Answers

7 votes
would be a. since KE = 1/2 m*v^2
User Beginner
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6.3k points
3 votes
KE = (1/2) · (1,451 kg) · (48 km/hr)² · (1000 m/km)² · (1 hr/3,600 sec)²

= (725.5) · (48 · 1000 · 1 / 3,600)² (kg) · (km·m·hr / hr·km·sec)²

= (725.5) · ( 40/3 )² · ( kg·m² / sec²)

= 128,978 joules (rounded)
User Tri Hoang
by
6.4k points
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