Question

You have a balloon containing 1 L of air at STP in a vacuum chamber. What will the volume of the balloon be when you reduce the pressure by half and increase the temperature to 373 K ?

Answer 1

P1V1/T1=P2V2/T2 P2=1/2 P1 V1=1 T1=298K

1 P1/298= (1/2) P1V2/373 cross P1

1/298=1/2V2/373
1/298=1/V2 746
v2=746/298
V2=2.5L

Answer 2

ANSWE: p1V1/T1 = p2V2/T2

at STP : p = 1.0 atm and T = 273 K

1.0 atm x 1.0 L / 273 K = 0.5 atm V / 373

V = 2.73 L