Question

Identify the value for C in the following equation that would make theconic section a hyperbola: 2x2 + y2 + 3x + 5y + 1 = 0

Answer 1

C = -1

Explanation:

We know that the general formula of hyperbola is the following

`((x-h)^2)/(a^2)-((y-k)^2)/(b^2)=1`

Which means that the sign must have y must be negative for it to be a hyperbola.

Therefore y must be equal to -1.

`2x^2-1y^2+3x+5y+1=0`