Question

An eagle carries a fish up 50 m into the sky using 90 N of force. How much work did the eagle do on the fish? (Work: W = Fd)

Answer 1

Answer: 4,500 J

Step-by-step explanation:

Work is defined as the product between the force applied to move an object (F) and the distance through which the object has been moved through (d), times the cosine of the angle
`\theta` between the direction of the force and the displacement:

`W=Fd cos \theta`

In this case, the work done by the eagle in lifting the fish is equal to the force applied by the eagle times the distance through which the fish has been moved, because the force is parallel to the displacement so
`cos \theta =1`:

`W=Fd`

In this problem, F=90 N and d=50 m. Therefore, the work done is

`W=Fd=(90 N)(50 m)=4,500 J`