Question

Write the equation of a line that is perpendicular to the given line and that passes through the given point. y+2=1/3(x-5);(-4,3)

Answer 1

Here, equation of a line, y + 2 = 1/3 (x -5)
slope = 1/3

Slope of the line which is perpendicular would be -3 [ reciprocal & opposite ]

Now, y - y1 = m(x-x1)
y - 3 = -3(x - (-4))
y - 3 = -3x - 12
y = -3x - 9

In short, Your Answer would be y = -3x - 9

Hope this helps!