Question

Solve for the dimensions of the rectangle. Area= length•widthThe length of a rectangle is 2cm greater than the width. The area is 80cm2. Find the length and width.

Answer 1

The length of a rectangle is 2cm greater than the width. The area is 80cm2. Find the length and width.

L=W+2

W=W

`\Delta=4+320=324`
`\begin{gathered} W=\frac{-2\pm\sqrt[]{324}}{2}=(-2\pm18)/(2) \\ W_1=(-20)/(2)=-10 \\ W_2=(16)/(2)=8 \end{gathered}`

The width should be positive, therefore W=8

L=W+2

L=8+2=10

The length is L=10