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What is the point slope form for 1/5 passing through its origins

User Hmnzr
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\stackrel{origin}{(\stackrel{x_1}{0}~,~\stackrel{y_1}{0})}\qquad \qquad \stackrel{slope}{m}\implies \cfrac{1}{5} \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{\cfrac{1}{5}}(x-\stackrel{x_1}{0})

User Prasad
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