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6xy (1/2x ^2 - 1/2xy + 1/2y ^2 )
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6xy (1/2x ^2 - 1/2xy + 1/2y ^2 )

User Collarblind
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3 votes
is this correct on what you typed above ->
\bf 6xy\left( \cfrac{1}{2x^2}-\cfrac{1}{2xy}+\cfrac{1}{2y^2} \right) ?
User Asktomsk
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