Question

The Reaction: _S+O2=_SO2
How many moles of sulfur must be burned to give 0.567 moles of SO2?

Answer 1

Moles ratio:

1 S + 1 O2 = 1 SO2

1 mole S -------------- 1 mole SO2
? moles S ------------ 0.567 moles SO2

0,567 x 1 / 1

= 0.567 moles of S

Answer 2

`0.567mol SO_(2)`

Step-by-step explanation:

We have the reaction

`S+ O_(2)\longrightarrow So_(2)`

we balance the equation

`S+ O_(2)\longrightarrow So_(2)`

In this case the equation is already balanced

We use stoichiometric relations to solve it.

we know that 1 mol of sulfur produces 1 mol of
`SO_(2)` (we know it by the coefficients of balancing of the equation, which in this are equal to 1)

Now how many moles of sulfur are needed to produce 0.567 moles of
`SO_(2)`

`1mol S\longrightarrow 1 mol SO_(2)\\ x\longrightarrow 0.567mol SO_(2)\\ x=(0.567 mol SO_(2).1molS)/(1molSO_2) =0.567mol SO_(2)`