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2. Given: ZMOP is a right angle RP I OP Prove: MO || RP

2. Given: ZMOP is a right angle RP I OP Prove: MO || RP-example-1
User Jackieyang
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1 Answer

13 votes
13 votes

Given that;


\begin{gathered} \measuredangle MOP\text{ is a right angle.} \\ \measuredangle MOP=90^0 \end{gathered}

And;


\vec{RP}\perp\vec{OP}

Since line RP is perpendicular to line OP, Angle RPO must be a right angle.


\measuredangle RPO=90^0

Recall that for two parallel lines intersected by a straight line, Same side interior angles are supplementary.


A+B=180^0

So, for line MO to be parallel to line RP, the sum of angle MOP and angle RPO must be equal to 180 degree.


\measuredangle MOP+\measuredangle RPO=90+90=180^0

Since the sum of angle MOP and angle RPO is equal to 180 degree, then line MO is parallel to line RP.


\begin{gathered} \text{ Since} \\ \measuredangle MOP+\measuredangle RPO=180^0 \\ \text{Then;} \\ MO\Vert RP​ \end{gathered}

Proved

2. Given: ZMOP is a right angle RP I OP Prove: MO || RP-example-1
User Luke Dupin
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3.2k points