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How much water needs to be added to 65 mL of 3.0 M stock solution to produce a 1.0 M diluted solution?

User Abonec
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1 Answer

15 votes
15 votes

To answer this question, we have to use the dilution rule, that is represented by the following equation:


C1V1=C2V2

Where C1 and C2 are the initial and final concentrations and V1 and V2 are the initial and final volumes.

Solve the equation for V2 to find the final volume:


\begin{gathered} V2=(C1V1)/(C2) \\ V2=(3.0M\cdot65mL)/(1.0M) \\ V2=195mL \end{gathered}

The final volume of the solutions has to be 195mL. Since we already have 65mL, we need to add 130mL of water to have 195mL in total.

It means that the correct answer is 130mL.

User Darkdog
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