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The product of two consecutive integers is three less than three times their sum. Find the integers

User Rico Yao
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1 Answer

4 votes
n * (n+1) = 3 (n + n+1) -3
n^2 +n = 3n + 3n + 3 - 3
n^2 -5n = 0
n * (n -5) = 0
n = 5
Check:
5 * 6 = 3 * (11) -3

User Clemens
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