Question

I’ve done all the other parts, I simply need you to graph the proabola!

Answer 1

Given

`y=x^2-4x+3`

Find

Graph the parabola of the given function

Step-by-step explanation

`y=x^2-4x+3`

solve the equation

`\begin{gathered} x^2-4x+3=0 \\ x^2-3x-x+3=0 \\ x(x-3)-(x-3)=0 \\ (x-1)(x-3)=0 \\ x=1,3 \end{gathered}`

vertex can be found by using the formula,

`-(b)/(2a)=-(-4)/(2)=2`

x = 2 , substitute this in equation to get y value,

y = -1

if x = 0 then y =3 and if y= 0 then x = 1, 3

Final Answer