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9 + 4 + (-1) +(-1) +...+ (-546) = 0X X80Σ (-3 + 10) = 0E=1

User Javicobos
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1 Answer

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15 votes

Answer

The sum of the sequence = -30072

Step-by-step explanation

We are given a sequence of numbers and asked to find the sum of the terms up until the last term given. The sequence given is

9, 4, -1,.............., -546

On careful observation of this sequence, we can see that it is an arithmetic progression with a common difference of -5 between consecutive terms.

Common difference = (n + 1)th term - nth term

= 4 - 9 Or -1 - 4

= -5

For an arithmetic progression, the formula for the last term is given as

Last term = a + (n - 1)d

where

L = last term = -546

a = first term = 9

n = number of terms in the sequence = ?

d = common difference = -5

So, we can solve for the number of terms

-546 = 9 + (n - 1)(-5)

-546 = 9 - 5n + 5

-546 = 14 - 5n

14 - 5n = -546

-5n = -546 - 14

-5n = -560

Divide both sides by -5

(-5n/-5) = (-560/-5)

n = 112

We can now use the formula for the sum of an arithmetic progression to find the sum of this sequence.


\text{Sum of an A.P. = }(n)/(2)\lbrack2a+(n-1)d\rbrack

We know all of these parameters now

Sum of this AP = (112/2) [(2 × 9) + (112 - 1)(-5)]

= 56 [18 + (111 × -5)]

= 56 [18 - 555]

= 56 [ -537]

= -30072

Hope this Helps!!!

User GeraldBiggs
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