Answer:
The actual distance between these two exhibits = 125 feet.
Explanation:
Given :
Two water fountains are 10 inches apart on a scale of drawing museum
The actual distance between them is 400 feet.
On the same drawing, the distance between two exhibits is 3.125 inches.
To Find : What is the actual distance between these two exhibits?
Solution :
Since Two water fountains are 10 inches apart on a scale of drawing museum and The actual distance between them is 400 feet.
⇒ 10 inches = 400 feet
So, 1 inch = 400/10
⇒1 inch = 40 feet
Since we are given that the distance between two exhibits is 3.125 inches.
So , the actual distance between two exhibits (i.e.in feet ) (Using 1 inch = 40 feet)
= 3.215*40
= 125 feet
Thus , The actual distance between these two exhibits = 125 feet.