2 Answers

James Cotter · Answer 1 · 2018-09-15T18:21:49+0000

Answer:

$\text{Total surface area of net pyramid}=80\text{ in}^2$

Explanation:

We have been given a net pyramid and we are asked to find the total surface area of our given pyramid.

The total surface area of our given pyramid will be equal to the area of 4 triangles plus area of middle square.

$\text{Area of triangle}=(1)/(2)*\text{Base*Height}$

$\text{Area of triangle}=(1)/(2)*\text{8 in}*\text{4 in}$

$\text{Area of triangle}=(1)/(2)* 32\text{ in}^2$

$\text{Area of triangle}=16\text{ in}^2$

$\text{Area of 4 triangles}=4* 16\text{ in}^2$

$\text{Area of 4 triangles}=64\text{ in}^2$

$\text{Area of middle square}=\text{4 in}*\text{4 in}$

$\text{Area of middle square}=16\text{ in}^2$

Now let us add these areas to find the total surface area of our given net pyramid.

$\text{Total surface area of net pyramid}=16\text{ in}^2+64\text{ in}^2$

$\text{Total surface area of net pyramid}=80\text{ in}^2$

Therefore, the total surface area of our given net pyramid is 80 square units.

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