Question

Miriam reduced a square photo by cutting 3 inches away from the length and the width so it will fit in her photo album. The area of the reduced photo is 64 square inches. In the equation (x – 3)2 = 64, x represents the side measure of the original photo. What were the dimensions of the original photo?

A. 11 inches by 11 inches
B. 5 inches by 5 inches
C. 3 + inches by 3 + inches
D. 3 inches by 3 inches

Answer 1

its A
because 64 divided by 8= 8 so I added the three originally taken away


hope it helps

Answer 2

Option A is correct

11 inches by 11 inches

Explanation:

Area of square (A) is given by:

`A = \text{Side} * \text{Side}`

As per the statement:

Miriam reduced a square photo by cutting 3 inches away from the length and the width so it will fit in her photo album.

The area of the reduced photo is 64 square inches.

Given the equation:

`(x-3)^2 = 64` where, x is the the side measure of the original photo.

Solve for x;

Take square root both sides we have;

`x-3 = √(64)`

⇒
`x-3 = 8`

Add 3 to both sides we have;

x-3+3 = 8+3

⇒x = 11 inches

Therefore, the dimensions of the original photo were : 11 inches by 11 inches