Question

Draw the major monobromination product formed by heating the following alkane with bromine.

Answer 1

The chemistry question asks for the drawing of the major monobromination product of an alkane, which involves substituting the most hydrogen of the most substituted carbon atom with a bromine atom to create a compound like 2-bromopentane.

Step-by-step explanation:

The question involves the concept of halogenation, specifically monobromination of alkanes using bromine (Br2). Through this reaction, a hydrogen atom in the alkane is substituted by a bromine atom. The most likely site of bromine addition is the most substituted carbon atom, due to the formation of the most stable free radical during the reaction mechanism. When applying this concept to draw the major monobromination product, we look for the carbon atom that, upon substitution, gives rise to the most stable intermediate.

As an example, let's consider monobromination of pentane. The major product would be 2-bromopentane, because the bromine atom will predominantly substitute a hydrogen atom from one of the middle carbon atoms (either C-2 or C-3), which are secondary carbons and form more stable free radicals than the primary carbons at the ends of the chain. Hence, the IUPAC name for the resultant compound would be 2-bromopentane.

Answer 2

A monobromination reaction of an alkane involves an alkane and bromine. The position of the hydrogen atom that will be substituted by the bromine free radical will depend on the order of the alkane. The bromine will attach to the carbon that has the most substituents.