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A. What is the probability that a five-card poker hand contains exactly one ace? b. What is the probability that a five-card poker hand contains cards of five different kinds?
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A. What is the probability that a five-card poker hand contains exactly one ace?

b. What is the probability that a five-card poker hand contains cards of five different
kinds?

User ANeves
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1 Answer

5 votes
Part (A):


\frac{\dbinom41\dbinom{48}4}{\dbinom{52}5}\approx0.2995

Part (B): Depends on what you mean by "different kind". If "kind" means "suit", well that's impossible, because there are only 4 suits so at least two of the cards must match suit.
User Tona
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