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4 FeCr2O7 + 8 K2CO3 + O2. = 2 Fe2O3 + 8 K2CrO4 + 8 CO2 based on this formula a) how many grams of O2 are required to produce 44.0grams of CO2? And b) how many moles of Fe2O3 will be produced from 6.8 moles
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4 FeCr2O7 + 8 K2CO3 + O2. = 2 Fe2O3 + 8 K2CrO4 + 8 CO2 based on this formula a) how many grams of O2 are required to produce 44.0grams of CO2? And b) how many moles of Fe2O3 will be produced from 6.8 moles of K2CO3?

User Erdem Ergin
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Hope this helps, have a nice day!
4 FeCr2O7 + 8 K2CO3 + O2. = 2 Fe2O3 + 8 K2CrO4 + 8 CO2 based on this formula a) how-example-1
User Qerr
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