Question

What is the mass of 0.714 moles of Mercury (I) Chloride (Hg2Cl2)?

A. 472.2 amu
B. 340.0 amu
C. 472.2 g
D. 337.2 g
E. Both A and C

Answer 1

Data:

m (Sample Mass) = ?
n (Number of moles) = 0.714 mol
MM (Molar Mass) of Mercury (I) Chloride (
`Hg_(2) Cl_(2)`)
Hg = 2*200.59 = 401.18 amu
Cl = 2*35.453 = 70.906 amu
----------------------------------------
Molar Mass
`Hg_(2) Cl_(2)` = 401.18 + 70.906 = 472.086 ≈ 472.09 amu or 472.09 g/mol

Formula:


`n = (m)/(MM)`

Solving:



`n = (m)/(MM)`

`0.714 = (m)/(472.09)`

`m = 337.07226\:\to\:\boxed{\boxed{m\approx 337 g}} \end{array}}\qquad\quad\checkmark`

Answer:
By approximation would be letter D) 337.2 g