Question

You place air in a sealed can at standard temperature and pressure (STP). You double its absolute temperature (K) while leaving the volume constant. What happens to the pressure?

Answer 1

The pressure triples.

Answer 2

Answer:Pressure of the air inside the sealed container will get change 2 atm when absolute temperature is doubled.

Step-by-step explanation:

According to question , Volume is constant

According to Gay Lussac's Law:

`Pressure\propto Temperature` (at constant temperature)

`(P_1)/(T_1)=(P_2)/(T_2)`

At STP, the temperature ,
`T_1=273 K`

At STP, the pressure =
`P_1=1 atm`

On doubling the absolute temperature the pressure changes
`P_2`:

On doubling the temperature=
`T_2=2* T_1`

`P_2=(1 atm* 2* 273 K)/(273 K)=2 atm`

Pressure of the air inside the sealed container will get change 2 atm when absolute temperature is doubled.