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2 votes
2n^2 - 20
n= 5
?????

User Spersico
by
7.7k points

2 Answers

3 votes
Use this:

n1,2 = -b +- √b²-4*a*c / 2a

a = 2n (2)
b = -20
c = -5 (you have to subtract 5 to get 0)
User AnythingIsFine
by
7.4k points
4 votes
2n^2-20=0
2n^2=20
n^2=20÷2
n^2=10
n=radical 10
User OdinX
by
8.1k points

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