Question

If your front lawn is 17.0 feet wide and 20.0 feet long, and each square foot of lawn accumulates 1150 new snow flakes every minute, how much snow (in kilograms) accumulates on your lawn per hour? Assume an average snow flake has a mass of 1.50 mg.

Answer 1

To find the amount of snow that accumulates on the lawn per hour, calculate the lawn area, determine snowflakes per hour, and convert to kilograms, resulting in 35.19 kg of snow accumulation per hour.

Step-by-step explanation:

To calculate the amount of snow that accumulates on the lawn in kilograms per hour, we need to use the given information: the lawn is 17.0 feet wide, 20.0 feet long, and each square foot accumulates 1150 snowflakes every minute, with each snowflake having a mass of 1.50 mg.

First, we calculate the area of the lawn in square feet: Area = Width x Length = 17.0 ft x 20.0 ft = 340 ft2.

Next, we determine the number of snowflakes that fall on the lawn every hour: Snowflakes per hour = 1150 snowflakes/ft2/min x 60 minutes/hour x 340 ft2 = 23,460,000 snowflakes/hour.

Then, convert the mass of the snowflakes to kilograms: Total mass = (23,460,000 snowflakes x 1.50 mg/snowflake) / 1,000,000 mg/kg = 35.19 kg.

Therefore, 35.19 kilograms of snow accumulates on the lawn per hour.

Answer 2

First, we solve the area of the front lawn by multiplying the width with the length.
A = l x w = (20 ft) x (17 ft)
A = 340 ft²
Each foot square will accumulate 1150 per minute. Please follow through the conversion that I am about to perform below.
(340 ft²) x (1150 new snow/ 1ft².min) x (60 min/1 hour) x (1.50 mg/1 new snow) x (1 g/1000 mg) x (1 kg/ 1 g) = 35.19 kilogram of new snow